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2x^2+28x=-66
We move all terms to the left:
2x^2+28x-(-66)=0
We add all the numbers together, and all the variables
2x^2+28x+66=0
a = 2; b = 28; c = +66;
Δ = b2-4ac
Δ = 282-4·2·66
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-16}{2*2}=\frac{-44}{4} =-11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+16}{2*2}=\frac{-12}{4} =-3 $
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